JEE MAIN - Chemistry (2018 - 15th April Evening Slot - No. 3)
The total number of optically active compounds formed in the following reactio is :
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Two
Four
Six
Zero
Explanation
The product has two chiral carbon atoms.
So, it has = 2n = 22 = 4 stereoisomers.
So, it has = 2n = 22 = 4 stereoisomers.
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