JEE MAIN - Chemistry (2018 - 15th April Evening Slot - No. 17)
In KO2, the nature of oxygen species and the oxydation state of oxygen atom are, respectively :
Oxide and $$-$$ 2
Superoxide and $$-$$ 1/2
Peroxide and $$-$$ 1/2
Superoxide and $$-$$ 1
Explanation
KO2 is called potassium superoxide. Here O$$_2^ - $$ is the superoxide ion.
Oxidation state of K is +1 and let oxidation state of oxygent atom is = x
$$\therefore\,\,\,$$ 1 + 2(x) = 0
$$ \Rightarrow $$$$\,\,\,$$ x = $$-$$ $${1 \over 2}$$
Oxidation state of K is +1 and let oxidation state of oxygent atom is = x
$$\therefore\,\,\,$$ 1 + 2(x) = 0
$$ \Rightarrow $$$$\,\,\,$$ x = $$-$$ $${1 \over 2}$$
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