JEE MAIN - Chemistry (2018 (Offline) - No. 5)

The major product formed in the following reaction is : JEE Main 2018 (Offline) Chemistry - Alcohols, Phenols and Ethers Question 151 English
JEE Main 2018 (Offline) Chemistry - Alcohols, Phenols and Ethers Question 151 English Option 1
JEE Main 2018 (Offline) Chemistry - Alcohols, Phenols and Ethers Question 151 English Option 2
JEE Main 2018 (Offline) Chemistry - Alcohols, Phenols and Ethers Question 151 English Option 3
JEE Main 2018 (Offline) Chemistry - Alcohols, Phenols and Ethers Question 151 English Option 4

Explanation

(1)

JEE Main 2018 (Offline) Chemistry - Alcohols, Phenols and Ethers Question 151 English Explanation 1

Here oxygen(O) has lone so it will attach on H+ of HI and H+ will attach with O atom to form oxonium ion.

(2)

JEE Main 2018 (Offline) Chemistry - Alcohols, Phenols and Ethers Question 151 English Explanation 2

As O is more electronegative atom, so it don't want to hold the positive charge so it will break bond to create 2o cation which is stable.

JEE Main 2018 (Offline) Chemistry - Alcohols, Phenols and Ethers Question 151 English Explanation 3

Now with this cation I$$-$$ ion is added.

(3) $$\,\,\,$$ On the other oxygen atom similar method is applied.

JEE Main 2018 (Offline) Chemistry - Alcohols, Phenols and Ethers Question 151 English Explanation 4

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