JEE MAIN - Chemistry (2017 - 9th April Morning Slot - No. 20)
What quantity (in mL) of a 45% acid solution of a mono-protic strong acid must
be mixed with a 20% solution of the same acid to produce 800 mL of a 29.875% acid
solution ?
320
325
316
330
Explanation
Let the volume of a monoprotic acid solution in mL be V
$${{V \times 45} \over {100}} + {{(800 - V)20} \over {100}} = {{800 \times 29.875} \over {100}}$$
$${{9V} \over {20}} + 160 - {V \over 5} = 239$$
$${{5V} \over {20}} = 79 \Rightarrow V = 316$$ mL
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