JEE MAIN - Chemistry (2017 - 9th April Morning Slot - No. 1)
The increasing order of the boiling points for the following compounds is :
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(III) < (IV) < (II) < (I)
(IV) < (III) < (I) < (II)
(II) < (III) < (IV) < (I)
(III) < (II) < (I) < (IV)
Explanation
B.P. $$ \propto $$ dipole moment
(I) C2H5OH : Hydrogen bonding - Hydrogen bonding > Dipole-Dipole
(II) C2H5Cl : Dipole-Dipole of C2H5Cl is more polar than C2H5OCH3
so, Dipole-Dipole C2H5Cl > Dipole-Dipole C2H5OCH3
(III) C2H5CH3 : No hydrogen bonding and dipole-dipole interaction
(IV) C2H5OCH3 : Dipole-Dipole
$$ \therefore $$ The increasing order of boiling points will be :
C2H5CH3 < C2H5OCH3 < C2H5Cl < C2H5OH
(I) C2H5OH : Hydrogen bonding - Hydrogen bonding > Dipole-Dipole
(II) C2H5Cl : Dipole-Dipole of C2H5Cl is more polar than C2H5OCH3
so, Dipole-Dipole C2H5Cl > Dipole-Dipole C2H5OCH3
(III) C2H5CH3 : No hydrogen bonding and dipole-dipole interaction
(IV) C2H5OCH3 : Dipole-Dipole
$$ \therefore $$ The increasing order of boiling points will be :
C2H5CH3 < C2H5OCH3 < C2H5Cl < C2H5OH
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