JEE MAIN - Chemistry (2016 - 9th April Morning Slot - No. 2)
Consider the following sequence for aspartic acid :
_9th_April_Morning_Slot_en_2_1.png)
The pI (isoelectric point) of aspartic acid is :
The pI (isoelectric point) of aspartic acid is :
1.88
3.65
5.74
2.77
Explanation
pI = $${{p{K_1} + p{K_R}} \over 2} = {{1.88 + 3.65} \over 2} = {{5.53} \over 2} = 2.765 \approx 2.77$$
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