JEE MAIN - Chemistry (2016 - 9th April Morning Slot - No. 1)

The test to distinguish primary, secondary and tertiary amines is :
Carbylamine reaction
C6H5SO2Cl
Sandmeyer’s reaction
Mustard oil test

Explanation

Hinsberg’s reagent (C6H5SO2Cl) forms monoalkyl sulphonamide with 1o amines which is soluble in KOH. With 2o amines it gives dialkyl sulphonamide which is insoluble in KOH and with 3o amines there is no reaction.

In mustard oil test, 1o amines on action of CS2 and HgCl2 give alkyl isothiocyanate having mustard oil smell. 2o amines react with CS2 but not with HgCl2 while 3o amines give no reaction. However, this test is not able to distinguish 2o and 3o amines.

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