JEE MAIN - Chemistry (2016 - 10th April Morning Slot - No. 15)
The rate law for the reaction below is given by the expression k [A] [B]
A + B $$ \to $$ Product
If the concentration of B is increased from 0.1 to 0.3 mole, keeping the value of A at 0.1 mole, the rate constant will be :
A + B $$ \to $$ Product
If the concentration of B is increased from 0.1 to 0.3 mole, keeping the value of A at 0.1 mole, the rate constant will be :
k
k/3
3k
9k
Explanation
Rate constant only depends on temperature only and it is independed of concentration of reactants.
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