JEE MAIN - Chemistry (2014 (Offline) - No. 8)
The ratio of masses of oxygen and nitrogen in a particular gaseous mixture is 1 : 4. The ratio of number of
their molecule is:
1: 8
3 : 16
1 : 4
7 : 32
Explanation
Given ratio of mass of O2 and N2 = 1 : 4
Let mass of O2 = w
and mass of N2 = 4w
$$\therefore$$ Number of moles of O2 = $${w \over {32}}$$
Number of molecules of O2 = $${w \over {32}}$$$$ \times $$NA
Number of moles of N2 = $${4w \over {28}}$$
Number of molecules of N2 = $${4w \over {28}}$$$$ \times $$NA
$$\therefore$$ Ratio of molecules of O2 and N2
= $${w \over {32}}$$$$ \times $$NA : $${4w \over {28}}$$$$ \times $$NA
= 7 : 32
Let mass of O2 = w
and mass of N2 = 4w
$$\therefore$$ Number of moles of O2 = $${w \over {32}}$$
Number of molecules of O2 = $${w \over {32}}$$$$ \times $$NA
Number of moles of N2 = $${4w \over {28}}$$
Number of molecules of N2 = $${4w \over {28}}$$$$ \times $$NA
$$\therefore$$ Ratio of molecules of O2 and N2
= $${w \over {32}}$$$$ \times $$NA : $${4w \over {28}}$$$$ \times $$NA
= 7 : 32
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