JEE MAIN - Chemistry (2014 (Offline) - No. 4)
In which of the following reactions H2O2 acts as a reducing agent?
1. H2O2 + 2H+ + 2e- $$\to$$ 2H2O
2. H2O2 - 2e- $$\to$$ O2 + 2H+
3. H2O2 + 2e- $$\to$$ 2OH-
4. H2O2 + 2OH- - 2e- $$\to$$ O2 + 2H2O
1. H2O2 + 2H+ + 2e- $$\to$$ 2H2O
2. H2O2 - 2e- $$\to$$ O2 + 2H+
3. H2O2 + 2e- $$\to$$ 2OH-
4. H2O2 + 2OH- - 2e- $$\to$$ O2 + 2H2O
1, 2
3, 4
1, 3
2, 4
Explanation
The reducing agent loses electron during redox reaction i.e. oxidises itself.
$$\left( 1 \right)\,\,\,\,\,\,{H_2}\mathop {{O_2}}\limits^{ - 1} + 2{H^ + } + 2{e^ - }\,\,\buildrel \, \over \longrightarrow \,\,2{H_2}\mathop O\limits^{ - 2} \,\,({\mathop{\rm Re}\nolimits} d.)$$
$$\left( 2 \right)\,\,\,\,\,\,{H_2}\mathop {{O_2}}\limits^{ - 1} \,\,\buildrel \, \over \longrightarrow \mathop {{O_2}}\limits^0 + 2{H^ + } + 2{e^ - }\,\,(Ox.)$$
$$\left( 3 \right)\,\,\,\,\,\,{H_2}\mathop {{O_2}}\limits^{ - 1} + 2{e^ - }\,\,\buildrel \, \over \longrightarrow \,\,2\mathop O\limits^{ - 2} {H^ - }\,\,(Red.)$$
$$\left( 4 \right)\,\,\,\,\,\,{H_2}O_2^{ - 1} + 2O{H^ - }\,\buildrel \, \over \longrightarrow \mathop {{O_2}}\limits^0 + {H_2}O + 2{e^ - }\,\,\left( {Ox.} \right)$$
$$\left( 1 \right)\,\,\,\,\,\,{H_2}\mathop {{O_2}}\limits^{ - 1} + 2{H^ + } + 2{e^ - }\,\,\buildrel \, \over \longrightarrow \,\,2{H_2}\mathop O\limits^{ - 2} \,\,({\mathop{\rm Re}\nolimits} d.)$$
$$\left( 2 \right)\,\,\,\,\,\,{H_2}\mathop {{O_2}}\limits^{ - 1} \,\,\buildrel \, \over \longrightarrow \mathop {{O_2}}\limits^0 + 2{H^ + } + 2{e^ - }\,\,(Ox.)$$
$$\left( 3 \right)\,\,\,\,\,\,{H_2}\mathop {{O_2}}\limits^{ - 1} + 2{e^ - }\,\,\buildrel \, \over \longrightarrow \,\,2\mathop O\limits^{ - 2} {H^ - }\,\,(Red.)$$
$$\left( 4 \right)\,\,\,\,\,\,{H_2}O_2^{ - 1} + 2O{H^ - }\,\buildrel \, \over \longrightarrow \mathop {{O_2}}\limits^0 + {H_2}O + 2{e^ - }\,\,\left( {Ox.} \right)$$
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