JEE MAIN - Chemistry (2014 (Offline) - No. 24)
The correct set of four quantum numbers for the valence elections of rubidium atom (Z= 37) is:
5, 1, 1, + 1/2
5, 1, 0, + 1/2
5, 0, 0, + 1/2
5, 0, 1, + 1/2
Explanation
The electronic configuration of Rubidium (Rb = 37):
1s22s22p63s23p63d104s24p65s1
As you can see last electron or valence electron enterin 5s subshell
So, the quantum numbers are n = 5, $$l$$ = 0, m = 0, s = $$ \pm {1 \over 2}$$
1s22s22p63s23p63d104s24p65s1
As you can see last electron or valence electron enterin 5s subshell
So, the quantum numbers are n = 5, $$l$$ = 0, m = 0, s = $$ \pm {1 \over 2}$$
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