JEE MAIN - Chemistry (2013 (Offline) - No. 26)
Consider the following reaction:
$$xMnO_4^- + yC_2O_4^{2-}$$ + zH+ $$\to$$ xMn2+ + 2yCO2 + $${z \over 2}{H_2}O$$
The value's of x, y and z in the reaction are, respectively :
$$xMnO_4^- + yC_2O_4^{2-}$$ + zH+ $$\to$$ xMn2+ + 2yCO2 + $${z \over 2}{H_2}O$$
The value's of x, y and z in the reaction are, respectively :
5, 2 and 16
2, 5 and 8
2, 5 and 16
5, 2 and 8
Explanation
After balancing the reaction we get
$$2MnO_4^- + 5C_2O_4^{2-}$$ + 16H+ $$\to$$ 2Mn2+ + 10CO2 + $$8{H_2}O$$
$$\therefore$$ $$x$$ = 2, $$y$$ = 5 and z = 16
$$2MnO_4^- + 5C_2O_4^{2-}$$ + 16H+ $$\to$$ 2Mn2+ + 10CO2 + $$8{H_2}O$$
$$\therefore$$ $$x$$ = 2, $$y$$ = 5 and z = 16
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