JEE MAIN - Chemistry (2013 (Offline) - No. 16)
The molarity of a solution obtained by mixing 750 mL of 0.5 (M) HCl with 250 mL of 2(M) HCl will be:
1.00 M
1. 75 M
0.975 M
0.875 M
Explanation
The formula for molarity of mixture of two substance is = $${{{M_1}{V_1} + {M_2}{V_2}} \over {{V_1} + {V_2}}}$$
Here $${M_1} = 0.5$$, $${V_1} = 750$$, $${M_2} = 2$$, $${V_2} = 250$$
$$\therefore$$ Molarity of mixture = $${{0.5 \times 750 + 2 \times 250} \over {750 + 250}}$$
= $${{375 + 500} \over {1000}}$$
= $${{875} \over {1000}}$$
= 0.875
Here $${M_1} = 0.5$$, $${V_1} = 750$$, $${M_2} = 2$$, $${V_2} = 250$$
$$\therefore$$ Molarity of mixture = $${{0.5 \times 750 + 2 \times 250} \over {750 + 250}}$$
= $${{375 + 500} \over {1000}}$$
= $${{875} \over {1000}}$$
= 0.875
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