JEE MAIN - Chemistry (2009 - No. 5)
Arrange the carbanions, $${(C{H_3})_3}\overline C $$, $$\overline C C{l_3}$$ , $${(C{H_3})_2}\overline C H$$, $${C_6}{H_5}\overline C H{}_2$$ in order of their decreasing stability :
$${(C{H_3})_2}\overline C H$$ > $$\overline C C{l_3}$$ > $${C_6}{H_5}\overline C H{}_2$$ > $${(C{H_3})_3}\overline C $$
$$\overline C C{l_3}$$ > $${C_6}{H_5}\overline C H{}_2$$ > $${(C{H_3})_2}\overline C H$$ > $${(C{H_3})_3}\overline C $$
$${(C{H_3})_3}\overline C $$ > $${(C{H_3})_2}\overline C H$$ > $${C_6}{H_5}\overline C H{}_2$$ > $$\overline C C{l_3}$$
$${C_6}{H_5}\overline C H{}_2$$ > $$\overline C C{l_3}$$ > $${(C{H_3})_3}\overline C $$ > $${(C{H_3})_2}\overline C H$$
Explanation
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