JEE MAIN - Chemistry (2008 - No. 12)
The treatment of $$C{H_3}MgX\,\,$$ with $$C{H_3}C \equiv C - H$$ produces
$$C{H_3} - CH = C{H_2}$$
$$C{H_3}C \equiv C - C{H_3}$$
$$C{H_4}$$
Explanation
Writing the reaction we get
So we find that $$C{H_4}$$ is produced in this reaction.
So we find that $$C{H_4}$$ is produced in this reaction.
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