JEE MAIN - Chemistry (2007 - No. 10)
The actinoids exhibits more number of oxidation states in general than the lanthanoids. This is
because :
the 5f orbitals are more buried than the 4f orbitals
there is a similarity between 4f and 5f orbitals in their angular part of the wave function
the actinoids are more reactive than the lanthanoids
the 5f orbitals extend further from the nucleus than the 4f orbitals
Explanation
NOTE : More the distance between nucleus and outer orbitals, lesser will be force of attraction on them. Distance between nucleus and $$5f$$ orbitals is more as compared to distance between $$4f$$ orbital and nucleus. So actinoids exhibit more number of oxidation states in general than the lanthanoids.
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