JEE MAIN - Chemistry (2006 - No. 42)
How many moles of magnesium phosphate Mg3(PO4)2 will contain 0.25 mole of oxygen atoms?
1.25 $$\times$$ 10-2
2.5 $$\times$$ 10-2
0.02
3.125 $$\times$$ 10-2
Explanation
In one Mg3(PO4)2 molecule no of oxygen atoms = 8
So if there is M mole of Mg3(PO4)2 molecules then no of moles of oxygen atoms is = M $$ \times $$ 8
According to question,
M $$ \times $$ 8 = 0.25
$$ \Rightarrow $$ M = 0.03125 = 3.125 $$\times$$ 10-2
So if there is M mole of Mg3(PO4)2 molecules then no of moles of oxygen atoms is = M $$ \times $$ 8
According to question,
M $$ \times $$ 8 = 0.25
$$ \Rightarrow $$ M = 0.03125 = 3.125 $$\times$$ 10-2
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