JEE MAIN - Chemistry (2004 - No. 33)
Which one of the following aqueous solutions will exhibit highest boiling point?
0.01 M Na2SO4
0.015 M glucose
0.015 M urea
0.01 M KNO3
Explanation
As$$\,\,\,\,\Delta {T_b}^b = {T_b} - {T_b}^o$$
Where $${T_b} = b.pt$$ of solution
$$T_b^o = b.pt$$ of solvent or
$${T_b} = T_b^o + \Delta {T_b}$$
NOTE : Elevation in boiling point is a colligative property, which depends upon the no. of particles. Thus greater the number of particles, greater is it elevation and hence greater will be its boiling point. $$$N{a_2}S{O_4}\,\,\rightleftharpoons\,\,2N{a^ + } + SO_4^{2 - }$$$
Since $$N{a_2}S{O_4}\,\,$$ has maximum number of particles $$(3)$$ hence has maximum boiling point.
Where $${T_b} = b.pt$$ of solution
$$T_b^o = b.pt$$ of solvent or
$${T_b} = T_b^o + \Delta {T_b}$$
NOTE : Elevation in boiling point is a colligative property, which depends upon the no. of particles. Thus greater the number of particles, greater is it elevation and hence greater will be its boiling point. $$$N{a_2}S{O_4}\,\,\rightleftharpoons\,\,2N{a^ + } + SO_4^{2 - }$$$
Since $$N{a_2}S{O_4}\,\,$$ has maximum number of particles $$(3)$$ hence has maximum boiling point.
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