JEE MAIN - Chemistry (2003 - No. 9)
For the reaction equilibrium
N2O4 (g) $$\leftrightharpoons$$ 2NO2 (g)
the concentrations of N2O4 and NO2 at equilibrium are 4.8 $$\times$$ 10-2 and 1.2 $$\times$$ 10-2 mol L-1 respectively. The value of Kc for the reaction is
N2O4 (g) $$\leftrightharpoons$$ 2NO2 (g)
the concentrations of N2O4 and NO2 at equilibrium are 4.8 $$\times$$ 10-2 and 1.2 $$\times$$ 10-2 mol L-1 respectively. The value of Kc for the reaction is
3 $$\times$$ 10-1 mol L-1
3 $$\times$$ 10-3 mol L-1
3 $$\times$$ 103 mol L-1
3.3 $$\times$$ 102 mol L-1
Explanation
$${K_c} = {{{{\left[ {N{O_2}} \right]}^2}} \over {\left[ {{N_2}{O_4}} \right]}} = {{\left[ {1.2 \times {{10}^{ - 2}}} \right]^2} \over {\left[ {4.8 \times {{10}^{ - 2}}} \right]}}$$
$$ = 3 \times {10^{ - 3}}\,mol/L$$
$$ = 3 \times {10^{ - 3}}\,mol/L$$
Comments (0)
