JEE MAIN - Chemistry (2003 - No. 53)
What volume of hydrogen gas at 273 K and 1 atm pressure will be consumed in obtaining 21.6 g of elemental boron (atomic mass = 10.8) from the reduction of boron trichloride by hydrogen?
67.2 L
44.8 L
22.4 L
89.6 L
Explanation
The reaction is
2BCl3 + 3H2 $$ \to $$ 2B + 6HCL
$$\therefore$$ 3 moles of hydrogen produces 2 moles of boron
So 2$$ \times $$10.8 gm = 21.6 gm of boron is produces from 3$$ \times $$22.4 = 67.2 L hydrogen
2BCl3 + 3H2 $$ \to $$ 2B + 6HCL
$$\therefore$$ 3 moles of hydrogen produces 2 moles of boron
So 2$$ \times $$10.8 gm = 21.6 gm of boron is produces from 3$$ \times $$22.4 = 67.2 L hydrogen
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