JEE MAIN - Chemistry (2002 - No. 42)
The integrated rate equation is Rt = log C0 - log Ct . The straight line graph is obtained by
plotting
time vs log Ct
$${1 \over {time}}$$ vs Ct
time vs Ct
$${1 \over {time}}$$ vs $${1 \over {{C_t}}}$$
Explanation
$$Rt = \log {C_o} - {{\mathop{\rm logC}\nolimits} _t}$$
It is clear from the equation that if we plot a graph between $$\log \,{C_t}$$ and time, a straight line with a slope equal to $$ - {k \over {2.303}}$$ and intercept equal to $$\log \,\left[ {{A_o}} \right]$$ will be obtained.
It is clear from the equation that if we plot a graph between $$\log \,{C_t}$$ and time, a straight line with a slope equal to $$ - {k \over {2.303}}$$ and intercept equal to $$\log \,\left[ {{A_o}} \right]$$ will be obtained.
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