JEE MAIN - Chemistry Hindi (2024 - 9th April Evening Shift - No. 11)
सूची I का मिलान सूची II से करेः
सूची I |
सूची II |
||
---|---|---|---|
(A) | गलनांक [K] | (I) | $$\mathrm{Tl > In > Ga > Al > B}$$ |
(B) | आयनिक त्रिज्या $$\left[\mathrm{M}^{+3} / \mathrm{pm}\right]$$ | (II) | $$\mathrm{B}>\mathrm{T} 1>\mathrm{Al} \approx \mathrm{Ga}>\mathrm{In}$$ |
(C) | $$ \Delta_{\mathrm{i}} \mathrm{H}_1\left[\mathrm{~kJ} \mathrm{~mol}^{-1}\right] $$ |
(III) | $$\mathrm{T} 1>\mathrm{In}>\mathrm{Al}>\mathrm{Ga}>\mathrm{B}$$ |
(D) | परमाणु त्रिज्या [pm] | (IV) | $$\mathrm{B}>\mathrm{A} 1>\mathrm{T} 1>\mathrm{In}>\mathrm{Ga}$$ |
नीचे दिए गए विकल्पों में से सही उत्तर को चुनेः
A-IV, B-I, C-II, D-III
A-I, B-II, C-III, D-IV
A-III, B-IV, C-I, D-II
A-II, B-III, C-IV, D-I
Explanation
A-IV, B-I, C-II, D-III
The correct matching is as follows :
गलनांक [K] corresponds to $$\mathrm{B < Al < Ga < In < Tl}$$, which is represented by (IV).
आयनिक त्रिज्या $$\left[\mathrm{M}^{+3} / \mathrm{pm}\right]$$ corresponds to $$\mathrm{B < Al \approx Ga < Tl < In}$$, which is represented by (I).
$$\Delta_{\mathrm{i}} \mathrm{H}_1\left[\mathrm{~kJ} \mathrm{~mol}^{-1}\right]$$ corresponds to $$\mathrm{B < Ga < Al < In < Tl}$$, which is represented by (II).
परमाणु त्रिज्या [pm] corresponds to $$\mathrm{B < Al < Ga < In < Tl}$$, which is represented by (III).
Thus, the correct matching is :
A-IV
B-I
C-II
D-III
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