JEE MAIN - Chemistry Hindi (2023 - 10th April Morning Shift - No. 9)
दिया गया है:
(A) $$2 \mathrm{CO}(\mathrm{g})+\mathrm{O}_2(\mathrm{g}) \rightarrow 2 \mathrm{CO}_2(\mathrm{g})$$ $$\quad$$ $$\Delta \mathrm{H}_1^\theta=-x \mathrm{~kJ} \mathrm{~mol}^{-1}$$
(B) $$\mathrm{C}$$(graphite) +$$\mathrm{O}_2(\mathrm{g}) \rightarrow \mathrm{CO}_2(\mathrm{g})$$ $$\quad$$ $$\Delta \mathrm{H}_2^\theta=-y \mathrm{~kJ} \mathrm{~mol}^{-1}$$
निम्नअभिक्रिया के लिए $$\Delta \mathrm{H}^\theta$$ है:
$$\mathrm{C}$$(graphite) $$+~\frac{1}{2} \mathrm{O}_2(\mathrm{g}) \rightarrow \mathrm{CO}(\mathrm{g})$$ is
$$\frac{x-2 y}{2}$$
$$\frac{x+2 y}{2}$$
$$2 y-x$$
$$\frac{2 x-y}{2}$$
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