JEE MAIN - Chemistry Hindi (2023 - 10th April Morning Shift - No. 22)

$$\mathrm{FeO}_4^{2-} \stackrel{+2.2 \mathrm{~V}}{\longrightarrow} \mathrm{Fe}^{3+} \stackrel{+0.70 \mathrm{~V}}{\longrightarrow} \mathrm{Fe}^{2+} \stackrel{-0.45 \mathrm{~V}}{\longrightarrow} \mathrm{Fe}^0$$

$$E_{FeO_4^{2 - }/F{e^{2 + }}}^\theta $$ $$x\times10^{-3}$$ $$\mathrm{V}$$ है। $$x$$ का मान है:

Answer
1825

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