JEE MAIN - Chemistry Hindi (2021 - 26th February Morning Shift - No. 3)
निम्नलिखित प्रतिक्रियाओं में A, B और C का पता लगाएं :
$$N{H_3} + A + C{O_2} \to {(N{H_4})_2}C{O_3}$$
$${(N{H_4})_2}C{O_3} + {H_2}O + B \to N{H_4}HC{O_3}$$
$$N{H_4}HC{O_3} + NaCl \to N{H_4}Cl + C$$
$$N{H_3} + A + C{O_2} \to {(N{H_4})_2}C{O_3}$$
$${(N{H_4})_2}C{O_3} + {H_2}O + B \to N{H_4}HC{O_3}$$
$$N{H_4}HC{O_3} + NaCl \to N{H_4}Cl + C$$
$$A - {O_2};B - C{O_2};C - N{a_2}C{O_3}$$
$$A - {H_2}O;B - {O_2};C - NaHC{O_3}$$
$$A - {H_2}O;B - {O_2};C - N{a_2}C{O_3}$$
$$A - {H_2}O;B - C{O_2};C - NaHC{O_3}$$
Comments (0)
