$$C{H_3}C{H_2}OH\mathrel{\mathop{\kern0pt\longrightarrow} \limits_{573K}^{Cu}} $$

$$C{H_3}C{H_2}OH\buildrel {Cr{O_3} - {H_2}S{O_4}} \over \longrightarrow $$

$$C{H_2} = C{H_2} + {O_2}\mathrel{\mathop{\kern0pt\longrightarrow} \limits_{{H_2}O}^{Pd(II)/Cu(II)}} $$

$$C{H_3}CN\mathrel{\mathop{\kern0pt\longrightarrow} \limits_{ii)\,{H_2}O}^{i)\,DIBAL - H}} $$