JEE MAIN - Chemistry Hindi (2020 - 6th September Morning Slot - No. 17)
प्रतिक्रिया के लिए
Fe2N(s) + $${3 \over 2}$$H2(g) ⇌ 2Fe(s) + NH3(g)
Fe2N(s) + $${3 \over 2}$$H2(g) ⇌ 2Fe(s) + NH3(g)
KC = Kp(RT)1/2
KC = Kp(RT)-1/2
KC = Kp(RT)
KC = Kp(RT)3/2
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