JAMB - Physics (2025 - No. 98)
Given that SQ = 10cm and SR = 6cm, the refractive index of the block of glass shown in the above figure is
1.67
0.60
0.30
2.33
Explanation
For a ray entering and exiting parallel faces of a glass slab, the refractive index is given by:
n = \(\frac{\text{real depth}}{\text{apparent depth}}\)
Where SR = 6cm is apparent depth, SQ = 10cm real depth.
n = \(\frac{10}{6}\) = 1.6666 ≈ 1.67
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