JAMB - Physics (2025 - No. 97)
Assuming E\(_1\), E\(_2\), and E\(_3\), are equal, then the total e.m.f of the arrangement will be given by
\(\frac{1}{\text{E}}\) = (\(\frac{1}{E_1}\) +\(\frac{1}{E_2}\)) + E\(_3\)
E = \(E_1\) + \(E_2\) + \(E_3\)
\(\frac{1}{\text{E}}\) = \(\frac{1}{E_1}\) + \(\frac{1}{E_2}\) + \(\frac{1}{E_3}\)
E = \(E_1\) = \(E_2\) = \(E_3\)
Explanation
Parallel connection does not add the voltages; it only increases the current capacity. Thus, total e.m.f. E = E\(_1\) = E\(_2\) = E\(_3\).
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