From the diagram, \(\alpha\) = 360 - 315 = 45º

x - component = 4 cos 45 = 4 x \(\frac{\sqrt{2}}{2}\) = 2\(\sqrt{2}\)

y - component = 4 sin 45 = 4 x - \(\frac{\sqrt{2}}{2}\) = - 2\(\sqrt{2}\)

Magnitude of vector = \(\sqrt{(2\sqrt{2})^2 + (-2\sqrt{2})^2}\) = \(\sqrt{16}\) = 4 NC\(^{-1}\)

Take the magnitude of the vector = 2\(\sqrt{2}\) based on the available option.