The pressure exerted by the water at the bottom of the reservoir is given by:

\(P = \frac{F}{A}\)

Given: \( F = 5000 \, \text{N} \) (weight of water), \( L = 10 \, \text{m} \) (length), \( B = 5 \, \text{m} \) (breadth)

Calculate the area \( A \):

\(A = L \times B = 10 \, \text{m} \times 5 \, \text{m} = 50 \, \text{m}^2\)

Calculate the pressure \( P \):

\(P = \frac{F}{A} = \frac{5000 \, \text{N}}{50 \, \text{m}^2} = 100 \, \text{Pa}\)