JAMB - Physics (2025 - No. 55)

From the above circuit, calculate the impedance ((\(\pi\) = \(\frac{22}{7}\), f = 50Hz)

86.7\(\Omega\)
163.5\(\Omega\)
204.8\(\Omega\)
16.3\(\Omega\)

Explanation

Given: Inductance: \( L = 0.5 \, \text{H} \), Resistance: \( R = 45 \, \Omega \), Frequency: \( f = 50 \, \text{Hz} \)

inductive reactance \( X_L \): \(X_L = 2 \pi f L = 2 \times \frac{22}{7} \times 50 \times 0.5 = \frac{1100}{7} \approx 157.14 \, \Omega\)
The impedance \( Z \):

\(Z = \sqrt{R^2 + X_L^2} = \sqrt{(45)^2 + (157.14)^2} = \sqrt{2025 + 24642.82} \approx \sqrt{26667.82} \approx 163.5 \, \Omega\).

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