JAMB - Physics (2025 - No. 44)
If the specific gravity of a liquid is 0.76, calculate its density((\(\rho_w\) = 1000Kgm\(^{-3}\))
760Kgm\(^{-3}\)
76Kgm\(^{-3}\)
7.6Kgm\(^{-3}\)
7600Kgm\(^{-3}\)
Explanation
Specific gravity (SG) is the ratio of the density of the liquid (\(\rho_l\)) to the density of water (\(\rho_w\)):
\( \mathrm{SG} = \frac{\rho_l}{\rho_w} \)
Rearranging for density:
\((\rho_l = \mathrm{SG} \times \rho_w = 0.76 \times 1000 = 760 \, \mathrm{kg \, m^{-3}}\)
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