JAMB - Physics (2025 - No. 33)

A machine has an efficiency of 80%. If the input work is 200J, the output work is?
250J
160J
120J
100J

Explanation

\(\text{Efficiency} = \frac{\text{Output Work}}{\text{Input Work}}\)

Given: \(\text{Efficiency} = 80\% = 0.8\), \(\text{Input Work} = 200 \text{ J}\)

Then, the output work is calculated as follows:

\(\text{Output Work} = 0.8 \times 200 = 160 \, \text{J}\)

Thus, the output work is: \(\text{Output Work} = 160 \, \text{J}\).

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