JAMB - Physics (2024 - No. 95)
The equivalent capacitance of the capacitors in the circuit above
\(\frac{5}{2}\)C
4C
\(\frac{3}{2}\)C
2C
Explanation
Capacitance in parallel = one at the top + one under = 2C
The two in the middle are in series = \(\frac{C}{2}\)
The equivalent capacitance of the capacitors in the circuit above = \(\frac{C}{2}\) + 2C = \(\frac{5}{2}\)C
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