JAMB - Physics (2024 - No. 62)
Using the diagram above, the effective force pushing it forward at an angle 60º is
25.00N
28.87N
38.50N
43.30N
Explanation
The effective force pushing it forward is the horizontal component of the force = F\(_x\) = F Cos\(\theta\)
F\(_x\) = F Cos\(\theta\) = 50 x Cos 60º = 50 x 0.5 = 25N
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