JAMB - Physics (2023 - No. 4)
A missile is launched with a speed of 75 ms-1 at an angle of 22° above the surface of a warship. Find the horizontal range achieved by the missile. Ignore the effects of air resistance.
[Take g = 10 ms-2]
[Take g = 10 ms-2]
195
271 m
391 m
136 m
Explanation
U= 75 \(ms^-1\) =22º, g= 10 \(ms^-2\) , R=?
R= \(\frac{U^2sin2\theta}{g}\)
⇒R= \(\frac{75^2×sin2(22)}{10}\)
⇒R= \(\frac{5625×Sin44}{10}\)
⇒R= \(\frac{5625×0.6947}{10}\)
⇒R= \(\frac{3907.69}{10}\)
⇒ 391m
Comments (0)
