Fx= 12cos32°-16cos26°  =  -4.20N  (right is taken +ve and left is taken -ve)

Fy=12sin32°+16sin26°-21 = -7.63N  (up is taken +ve and down is taken -ve)

\(R^2\)= 4.202+7.632

⇒\(R^2\) = 75.86

⇒ R=√75.86

∴R = 8.71 N

tan θ=\(\frac{opp}{adj}\)

⇒tan θ=\(\frac{7.63}{4.20}\)

⇒tan θ =1.8095

⇒ θ = \(tan^-1\) (1.8095)

 θ = 61°

∴The angle of the resultant force with the x-axis is 61°

 

 

 

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