JAMB - Physics (2022 - No. 7)
A car starts from rest and covers a distance of 40 m in 10 s. Calculate the magnitude of its acceleration
3.20 ms\(^{-2}\)
0.25 ms\(^{-2}\)
0.80 ms\(^{-2}\)
4.00 ms\(^{-2}\)
Explanation
S = ut + \(\frac{1}{2}\)at\(^2\)
40 = 0 x 10 + \(\frac{1}{2}\)a x 10\(^2\)
50a = 40
a = \(\frac{40}{50}\)
= 0.8m/s\(^2\)
40 = 0 x 10 + \(\frac{1}{2}\)a x 10\(^2\)
50a = 40
a = \(\frac{40}{50}\)
= 0.8m/s\(^2\)
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