JAMB - Physics (2021 - No. 10)
A source of sound produces waves in air of wavelength 1.65m. If the speed of sound in air is 330ms\(^{-1}\), the period of vibration in air is?
200
0.005
0.5
0.02
Explanation
V = \(\frac{\lambda}{T}\)
: v = 330ms\(^{-1}\)
\(\lambda\) = 1.65m
T = ?
330 = 1.65
T = \(\frac{1.65}{330}\) = 0.005s
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