JAMB - Physics (2019 - No. 48)

Three resistors with resistance 200Ω, 500Ω and 1kΩ are connected in series. A 6v battery is connected to either end of the combination. Calculate the potential difference between the ends of 200Ω resistance.
0.71V
0.7V
0.82V
0.8V

Explanation

 

Req = 200 + 500 + 1000 = 1700Ω

P.d (across 200Ω) = 200
1700
× 6 = 0.71V

Comments (0)

Advertisement