JAMB - Physics (2017 - No. 28)

From the diagram above, calculate the energy stored in the capacitor

4.0 x 10\(^{-2}\)J

4.0 x 10\(^{-4}\)J

8.0 x 10\(^{-4}\)J

8.0 x 10\(^{-2}\)J

c = 8µF, v = 10v

Energy stored = \(\frac{1}{2}\) cv²

= \(\frac{1}{2}\) × (8 × 10− 6) × 10²

= 4 × 10\(^{-4}\)