JAMB - Physics (2015 - No. 31)
If a mango fruit dropped at a height of 50 meters. How long does it reach the ground? (take g = 10m/s2)
2 sec
3 sec
4sec
3.2sec
Explanation
From S = ut + ½gt2
u = 0ms-1
50 = (0 × t) + ½(10)(t2)
50 = 5.0t2
t2 =50/5
t = √10
t = 3.2sec
u = 0ms-1
50 = (0 × t) + ½(10)(t2)
50 = 5.0t2
t2 =50/5
t = √10
t = 3.2sec
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