JAMB - Physics (2013 - No. 31)
A cell of emf 1.5V is connected in series with a 1Ω resistor and a current of 0.3A flows through the resistor. Find the internal resistance of the cell
4.0Ω
3.0Ω
1.5Ω
1.0Ω
Explanation
r = \(\frac{E}{I} - R\)
r = \(\frac{1.5}{0.3} - 1\)
r = 4\(\Omega\)
r = \(\frac{1.5}{0.3} - 1\)
r = 4\(\Omega\)
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