JAMB - Physics (2013 - No. 14)

A gas at a pressure of 105Nm-2expands from 0.6m-3 to 1.2m3 at constant temperature, the work done is
7.0 x 106J
6.0 x 10 6J
6.0 x 10 5J
6.0 x 10 4J

Explanation

W = \(\frac{W_1 \times V_1}{V_2}\)

W = \(\frac{10 \times 0.6}{1.2}\)

W = 6.0 x 10 4J

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