JAMB - Physics (2012 - No. 4)
A car starts from rest and moves with a uniform acceleration of 30ms-2 for 20s. Calculate the distance covered at the end of the motion
6km
12km
18km
24km
Explanation
S = \(ut + \frac{1}{2}at^2\)
S = \(0 \times 2 + \frac{1}{2} \times 30 \times 20^2\)
S = \(0 \times 2 + \frac{1}{2} \times 30 \times 20^2\)
Comments (0)
