JAMB - Physics (2012 - No. 25)
A pinhole camera is placed 300m in front of a building so that the image is formed on a screen 5cm from the the pinhole. If the image is 2.5cm high, the height of the building will be
25m
50m
100m
150m
Explanation
==> \(\frac{v}{u}\) = \(\frac{hi}{ho}\)
==> \(\frac{5}{300}\) = \(\frac{2.5}{ho}\)
= 150m
==> \(\frac{5}{300}\) = \(\frac{2.5}{ho}\)
= 150m
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