JAMB - Physics (2012 - No. 10)
If a load of 1 kg stretches a cord by 1.2cm, what is the force constant of the cord? {g=10ms-2}
866Nm-1
833Nm-1
769Nm-1
667Nm-1
Explanation
K = \(\frac{F}{e}\)
K = \(\frac{1 \times 10}{\frac{0.2}{100}}\)
K = \(\frac{10}{12} \times \frac{1000}{1}\)
K = \(\frac{1 \times 10}{\frac{0.2}{100}}\)
K = \(\frac{10}{12} \times \frac{1000}{1}\)
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