JAMB - Physics (2011 - No. 45)
In the circuit above, three resistors, 2Ω, 4Ω and 12Ω are connected in parallel and a 12V battery is connected across the combination. The current flowing through the 12Ω resistors is
14.4 A
1.0 A
3.2 A
9.6 A
Explanation
I = \(\frac{V}{R}\) from Ohm's law
I = \(\frac{12}{12}\) = 1A.
Comments (0)
