JAMB - Physics (2008 - No. 6)

If a body mass 5kg is thrown vertically upwards with velocity u,at what height will the potential energy equal to the kinetic energy?

h =(u)²/g

h = (u)²/4g

h = (2u)²/g

h = (u)²/2g

From V2 = U2 + 2as
O = U 2 - 2gH, since at maximum height H, the final velocity, v = O.

when K.E = P.E
∴ H = (U)2/2g
Halfway is the height / 2

PE = KE at (1)/2 H = (U)2 /2g x (1/2) = U2 / 4g